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872415-80-0

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872415-80-0 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 872415-80-0 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 8,7,2,4,1 and 5 respectively; the second part has 2 digits, 8 and 0 respectively.
Calculate Digit Verification of CAS Registry Number 872415-80:
(8*8)+(7*7)+(6*2)+(5*4)+(4*1)+(3*5)+(2*8)+(1*0)=180
180 % 10 = 0
So 872415-80-0 is a valid CAS Registry Number.

872415-80-0Relevant articles and documents

Reactivity studies of iridiuni(III) porphyrins with methanol in alkaline media

Cheung, Chi Wai,Fung, Hong Sang,Lee, Siu Yin,Qian, Ying Ying,Chan, Yun Wai,Chan, Kin Shing

experimental part, p. 1343 - 1354 (2010/05/14)

Ir(ttp)Cl(CO) (la; ttp = 5,10,15,20-tetrakis(p-tolyl)porphyrinato dianion) was found to cleave the C-O bond of CH3OH at 200 C to give Ir(ttp)CH3 (3a). Addition of KOH promoted the reaction rate and gave a higher yield of Ir(ttp)CH3 in 70% yield in 1 day. Mechanistic studies suggest that, in the absence of KOH, Ir(ttp)Cl(CO) reacts with CH 3OH initially to give Ir(ttp)OCH3, which then undergoes β elimination to produce Ir(ttp)H (4a). Ir(ttp)H further reacts slowly to cleave the C-O bond of CH3OH, likely via cr-bond metathesis, to give Ir(ttp)CH3. In the presence of KOH, Ir(ttp)Cl(CO) initially reacts with KOH more rapidly to give Ir(ttp)OH, which then cleaves the 0-H bond of CH3OH by metathesis to give Ir(ttp)OCH3. Ir(ttp)OCH 3 further isomerizes via /3-hydride elimination/reinsertion to give Ir(Up)CH2OH and concurrently undergoes base-assisted /3-proton elimination to give Ir(ttp)-K+ (5a). Ir(ttp)CH.20H subsequently condenses with CH3OH to form. Ir(Up)CH2OCH3 (2). Finally, Ir(ttp)-K+ cleaves the C-O bond in CH3OH, most probably via nucleophilic substitution, to give Ir(ttp)CH3. Ir(ttp)CH 2OCH3 also serves as the precursor of Ir(ttp)-K+ as it undergoes nucleophilic substitution by KOH to give Ir(ttp)-K+.

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