4100-80-5Relevant articles and documents
-
Bergmann,Blum-Bergmann
, p. 1573 (1937)
-
Synthesis of Cyclic Anhydrides via Ligand-Enabled C–H Carbonylation of Simple Aliphatic Acids
Herron, Alastair N.,Yu, Jin-Quan,Zhuang, Zhe
supporting information, p. 16382 - 16387 (2021/06/23)
The development of C(sp3)–H functionalizations of free carboxylic acids has provided a wide range of versatile C?C and C?Y (Y=heteroatom) bond-forming reactions. Additionally, C–H functionalizations have lent themselves to the one-step preparation of a number of valuable synthetic motifs that are often difficult to prepare through conventional methods. Herein, we report a β- or γ-C(sp3)–H carbonylation of free carboxylic acids using Mo(CO)6 as a convenient solid CO source and enabled by a bidentate ligand, leading to convenient syntheses of cyclic anhydrides. Among these, the succinic anhydride products are versatile stepping stones for the mono-selective introduction of various functional groups at the β position of the parent acids by decarboxylative functionalizations, thus providing a divergent strategy to synthesize a myriad of carboxylic acids inaccessible by previous β-C–H activation reactions. The enantioselective carbonylation of free cyclopropanecarboxylic acids has also been achieved using a chiral bidentate thioether ligand.
(Meth) acrylic ester and manufacturing method thereof (by machine translation)
-
Paragraph 0058, (2019/12/04)
(Meth) acrylic acid ester of [be] hydrophobic properties. (1) (Meth) acrylic ester represented by the formula [a]. R1 Is H or methyl; R3 Alkyl, cycloalkyl, aryl or aralkyl; R21 , R22 , R23 Each independently is H, alkyl or cycloalkyl is not one of at least 2 H; Z1 The divalent chain hydrocarbon substituted of unsubstituted C1 a-20/2, 2 // hetero-substituted of unsubstituted C1 a-20 free of divalent cyclic hydrocarbon or a single bond; Z2 The divalent chain hydrocarbon of C1 c 12 2, Z3 The (R21 R22 R23 ) Coupled with a free cyclic hydrocarbon containing heteroatoms C C - C3 d 10/forming atomic group; n is an integer of 0 - 3; m is an integer of 1 - 18[Drawing] no (by machine translation)